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Edited by gaara at 2015-3-14 17:28
Yes, the equation gives me, for the screen alone: (but you're right, I should measure it at the end, when all will be active)
R1= 0.88x12 = 13.63
If I want to try first 0.90 A:
R2 = 0.9x12 = 13.33
So, the resistance I should add = R1-R2 = 13.63-13.33 = 0.3
Is my reasoning good ?
For the power (W), maybe I can use cheaper resistances for my tries (they can heat a little, don't matter), and when I have found the good one, I buy the good W value ? what do you think ? (sorry for all this questions!)
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